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x^2+350x-30000=0
a = 1; b = 350; c = -30000;
Δ = b2-4ac
Δ = 3502-4·1·(-30000)
Δ = 242500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{242500}=\sqrt{2500*97}=\sqrt{2500}*\sqrt{97}=50\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(350)-50\sqrt{97}}{2*1}=\frac{-350-50\sqrt{97}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(350)+50\sqrt{97}}{2*1}=\frac{-350+50\sqrt{97}}{2} $
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